# I = -1

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squaring both sides . 1-i=a^2 - b^2 +2 i a b. real=real ,imaginary = imaginary. a^2 - b^2 =1 --->1. 2 a b = -1 --->2. squaring equation 1 & 2 than adding them Access Google Drive with a free Google account (for personal use) or Google Workspace account (for business use).

20.01.2021

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### 1/i = -i is correct, as far as I know. But I can't work out a demonstration for it. Worse, when I try, I get the wrong result and I can't figure out why: 1/i = 1/SQRT(-1) = SQRT(1)/SQRT(-1) = SQRT(1/-1) = SQRT(-1/1) = SQRT(-1)/SQRT(1) = i/1 = i I'd appreciate it if someone could point out where I'm going wrong there. And also prove that 1/i

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2 a b = -1 --->2.

Also. 1 + i = e ln(1 + i). Thus (1 + i) 2 - i = e (2 - i) ln(1 + i) Thus using equation (1… Discover recipes, home ideas, style inspiration and other ideas to try. Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor. Find local businesses, view maps and get driving directions in Google Maps.

Usually we reduce things to the "simplest" terms for display -- saying $0$ is a lot cleaner than saying $1-1$ for example. 27.07.2017 1/i = -i is correct, as far as I know. But I can't work out a demonstration for it. Worse, when I try, I get the wrong result and I can't figure out why: 1/i = 1/SQRT(-1) = SQRT(1)/SQRT(-1) = SQRT(1/-1) = SQRT(-1/1) = SQRT(-1)/SQRT(1) = i/1 = i I'd appreciate it if someone could point out where I'm going wrong there. And also prove that 1/i Google allows users to search the Web for images, news, products, video, and other content. 28.09.2014 Share videos, music and pictures, follow friends and keep track of what you enjoy! Join us Hi Eilis, You need to use the exponential form to calculate this power.

Worse, when I try, I get the wrong result and I can't figure out why: 1/i = 1/SQRT(-1) = SQRT(1)/SQRT(-1) = SQRT(1/-1) = SQRT(-1/1) = SQRT(-1)/SQRT(1) = i/1 = i I'd appreciate it if someone could point out where I'm going wrong there. And also prove that 1/i i We can compute this by multiplying both numerator and denominator by the conjugate, 1+i, of the denominator. ((1+i)/(1-i))*((1+i)/(1+i)) = (1+2i+i^2)/(1-i^2) We There are multiple ways of writing out a given complex number, or a number in general. Usually we reduce things to the "simplest" terms for display -- saying $0$ is a lot cleaner than saying $1-1$ for example. Dec 30, 2011 · 1-i)^1/2=a+i b. squaring both sides .

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The short form(a += 1) has the option to modify a in-place , instead of creating a new object representing the sum and rebinding it back to the same name(a = a + 1).So,The short form(a += 1) is much efficient as it doesn't necessarily need to make a copy of a unlike a = a + 1. Create an account or log in to Instagram - A simple, fun & creative way to capture, edit & share photos, videos & messages with friends & family. Complex number: 1-i Absolute value: abs(the result of step No. 1) = abs(1-i) = |(1-i)| = √ 1 2 + (-1) 2 = 1.4142136The absolute value of a complex number (also called the modulus) is a distance between the origin (zero) and the image of a complex number in the complex plane.